Ncert Solutions Class 12 Chapter 2 Inverse Trigonometric Functions Exercise 2.2 Question 8

Find the values of each of the following:

8. (tan^{-1}[2cos(2sin^{-1}{frac{1}{2}})]).


Inverse Trigonometric Functions

Exercise 2.2

Ncert solutions class 12 chapter 2 exercise 2

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Class 12

Inverse Trigonometric Functions

Exercise 2.2

Prove the following:

1. (3sin^{-1}{x}=sin^{-1}(3x-4x^3)), (xin[-frac{1}{2},frac{1}{2}]).

2. (3cos^{-1}{x}=cos^{-1}(4x^3-3x)), (xin[frac{1}{2},1]).

Write the following functions in the simplest form:

3. (tan^{-1}{frac{sqrt{1+x^2}-1}{x}}), (xne {0}).

4. (tan^{-1}(sqrt{frac{1-cosx}{1+cosx}})),(0<x<pi).

5. (tan^{-1}(frac{cosx-sinx}{cosx+sinx})), (-frac{pi}{4}<x<frac{3pi}{4}).

6. (tan^{-1}{frac{x}{sqrt{a^2-x^2}}}), (|x|<a).

7. (tan^{-1}(frac{3a^2x-x^3}{a^3-3ax^2})), (a>0;-frac{a}{sqrt3}<x<frac{a}{sqrt3}).

Find the values of each of the following:

8. (tan^{-1}[2cos(2sin^{-1}{frac{1}{2}})]).

9. (tan^{-1}[sin^{-1}{frac{2x}{1+x^2}}+cos^{-1}{frac{1-y^2}{1+y^2}}]), (|x|<1, y>0) and (xy<1).

Find the values of each of the expressions in Exercises 10 to 15.

10. (sin^{-1}(sin{frac{2pi}{3}})).

11. (tan^{-1}(tan{frac{3pi}{4}})).

12. (tan(sin^{-1}{frac{3}{5}}+cot^{-1}{frac{3}{2}})).

13. (cos^{-1}(cos{frac{7pi}{6}})).

(A) (frac{7pi}{6})

(B) (frac{5pi}{6})

(C) (frac{pi}{3})

(D) (frac{pi}{6})

14. (sin(frac{pi}{3}-sin^{-1}(-frac{1}{2}))).

(A) (frac{1}{2})

(B) (frac{1}{3})

(C) (frac{1}{4})

(D) (1)

15. (tan^{-1}{sqrt3}-cot^{-1}({-sqrt3})) is equal to:

(A) (pi)

(B) (-frac{pi}{2})

(C) (0)

(D) (2sqrt3)



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