Ncert Solutions Class 12 Chapter 1 Inverse Trigonometric Functions Exercise 2.1 Question 14

14. (tan^{-1}{sqrt{3}}-sec^{-1}(-2)) is equal to:

(A) (pi)

(B) (-frac{pi}{3})

(C) (frac{pi}{3})

(D) (frac{2pi}{3})

Inverse Trigonometric Functions

Exercise 2.1

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Class 12

Inverse Trigonometric Functions

Exercise 2.1

Find the principal values of the following:

1. (sin^{-1}({-frac{1}{2}}))

2. (cos^{-1}({frac{sqrt{3}}{2}}))

3. (cosec^{-1}(2))

4. (tan^{-1}(-sqrt{3}))

5. (cos^{-1}({-frac{1}{2}}))

6. (tan^{-1}(-1))

7. (sec^{-1}({frac{2}{sqrt 3}}))

8. (cot^{-1}(sqrt 3))

9. (cos^{-1}({-frac{1}{sqrt 2}}))

10. (cosec^{-1}(-sqrt{2}))

Find the values of the following:

11. (tan^{-1}(1))+(cos^{-1}({-frac{1}{sqrt 2}}))+(sin^{-1}({-frac{1}{sqrt 2}})).

12. (cos^{-1}({frac{1}{sqrt 2}}))+2(sin^{-1}({frac{1}{sqrt 2}})).

13. If (sin^{-1}x=y), then

(A) (0le ylepi)

(B) (-frac{pi}{2}le y le -frac{pi}{2})

(C) (0 < y <pi)

(D) (-frac{pi}{2} < y < -frac{pi}{2}) 

14. (tan^{-1}{sqrt{3}}-sec^{-1}(-2)) is equal to:

(A) (pi)

(B) (-frac{pi}{3})

(C) (frac{pi}{3})

(D) (frac{2pi}{3})

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