Real Numbers Class 10 Mcq Test (100101)chillimathMarch 29, 2023class 10, mcq, Ncert, Real Numbers Real Numbers Class 10 Multiple Choice Test/10 10 votes, 4.5 avg 401 Real Numbers Class 10 (1001)Challenge Yourself ... 1 / 10Given that HCF(26, 91) = 13, then LCM of (26, 91) is:(a) 2366 (b) 182(c) 91(d) 364 A B C D 2 / 10 \((\sqrt{2}-\sqrt{3})(\sqrt{3}+\sqrt{2})\) is:(a) A rational number (b) a whole number (c) an irrational number (d) a natural number A B C D 3 / 10If two positive integers p and q can be expressed as p=ab2 and q=a3b, a, b being prime numbers, then LCM(p, q) is:(a) ab (b) a2b2 (c) a3b2 (b) a3b3 A B C D 4 / 10If p, q are two consecutive natural numbers, then HCF(p, q) is:(a) q(b) p(c) 1(d) pq A B C D 5 / 10The largest number which divides 71 and 126, leaving remainders 6 and 9 respectively is:(a) 1750(b) 13 (c) 65 (d) 875 A B C D 6 / 10If \(x=2^3 \times 3 \times 5^2\), \(y=2^2 \times 3^3\), then HCF(x, y) is:(a) 12(b) 108(c) 6(d) 36 A B C D 7 / 10The least number that is divisible by all the numbers from 1 to 10 (both inclusive) is:(a) 10(b) 100 (c) 504 (d) 2520 A B C D 8 / 10If two integers a and b are written as a = x3y2 and b = xy4; x, y are prime numbers, then H.C.F.(a, b) is:(a) x3y3 (b) x2y2(c) xy(d) xy2 A B C D 9 / 10Given that HCF(253, 440) = 11 and LCM(253, 440) = 253×R. The value of R is:(a) 400(b) 40(c) 440(d) 253 A B C D 10 / 10If p, q are two prime numbers, then LCM(p, q) is:(a) 1(b) p(c) q(d) pq A B C D Your score is LinkedIn Facebook Twitter 0% Restart quiz Please rate this quiz Send feedback ResourcesNcert SolutionsNcert Exemplar Solutions