Ncert Solutions Class 10 Chapter 5 Arithmetic Progressions Exercise 5.4 Question 3

3. A ladder has rungs 25 cm apart. The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and bottom rungs are (2frac{1}{2}) m apart, what is the length of the wood required for the rungs?

Arithmetic Progressions

Exercise 5.4

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Class 10

Arithmetic Progressions

Exercise 5.4

1. Which term of the A.P. 121, 117, 113 … is its first negative term?

2. The sum of the third and the seventh terms of an A.P is 6 and their product is 8. Find the sum of first sixteen terms of the A.P.

3. A ladder has rungs 25 cm apart. The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. If the top and bottom rungs are (2frac{1}{2}) m apart, what is the length of the wood required for the rungs?

4. The houses of a row are number consecutively from 1 to 49. Show that there is a value of x such that the sum of numbers of the houses preceding the house numbered x is equal to the sum of the number of houses following it. Find this value of x.

5. A small terrace at a football ground comprises of 15 steps each of which is 50 m long and built of solid concrete. Each step has a rise of 1/4 m and a tread of 1/2 m. calculate the total volume of concrete required to build the terrace.

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