If (\begin{vmatrix}x & 2 \18 & x \end{vmatrix})=(\begin{vmatrix}6 & 2 \18 & 6 \end{vmatrix}), then x is equal to:

8. If (begin{vmatrix}x & 2 \18 & x end{vmatrix})=(begin{vmatrix}6 & 2 \18 & 6 end{vmatrix}), then x is equal to:

(A) 6

(B) ±6

(C) -6

(D) 0


Determinants

Exercise 4.1

Ncert Solutions class 12 chapter 4 exercise 1 question 8

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Class 12

Determinants

Exercise 4.1

Evaluate the determinants in Exercise 1 and 2.

1. (begin{vmatrix}2 & 4 \ -5 & -1end{vmatrix})

2. (i) (begin{vmatrix}cosθ & -sinθ \ sinθ & cosθend{vmatrix})

(ii) (begin{vmatrix}x^2-x+1 & x-1 \ x+1 & x+1end{vmatrix})

3. If (A=begin{bmatrix}1 & 2 \ 4 & 2end{bmatrix}), then show that |2A|=4|A|.

4. If  (A=begin{vmatrix}1 & 0 & 1 \ 0 &  1 & 2 \ 0 & 0 & 4 end{vmatrix}), then show that |3A|=27|A|.

5. Evaluate the determinants

(i) (begin{vmatrix}3 & -1 & -2 \ 0 & 0 & -1 \ 3 & -5 & 0 end{vmatrix})

(ii) (begin{vmatrix}3 & -4 & 5 \ 1 &  1 & -2 \ 2 & 3 & 1 end{vmatrix})

(iii) (begin{vmatrix}0 & 1 & 2 \ -1 &  0 & -3 \ -2 & 3 & 0 end{vmatrix})

(iv) (begin{vmatrix}2 & -1 & -2 \ 0 &  2 & -1 \ 3 & -5 & 0 end{vmatrix})

6. If (A=begin{vmatrix}1 & 1 & -2 \ 2 &  1 & -3 \ 5 & 4 & -9 end{vmatrix}), find |A|.

7. Find values of x, if 

(i) (begin{vmatrix}2 & 4 \5 & 1 end{vmatrix})=(begin{vmatrix}2x & 4 \6 & x end{vmatrix})

(ii) (begin{vmatrix}2 & 3 \4 & 5 end{vmatrix})=(begin{vmatrix}x & 3 \2x & 5 end{vmatrix})

8. If (begin{vmatrix}x & 2 \18 & x end{vmatrix})=(begin{vmatrix}6 & 2 \18 & 6 end{vmatrix}), then x is equal to:

(A) 6

(B) ±6

(C) -6

(D) 0



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