Lines and Angles Class 9 Mcq Test (90601)
Lines and Angles Class 9 Multiple Choice Test Resources Menu Ncert Solutions Exemplar Solutions Assignments Activities MCQ’s
Lines and Angles Class 9 Multiple Choice Test Resources Menu Ncert Solutions Exemplar Solutions Assignments Activities MCQ’s
7. ABCD is a trapezium in which AB || CD and AD = BC (see Fig.). Show that: (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint :Extend AB and draw…
6. ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD (see Fig.). Show that:(i) ΔAPB ≅ ΔCQD (ii) AP = CQ Quadrilaterals Exercise 8.1 Previous Next Class 9 Quadrilaterals Exercise 8.1…
5. In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ (see Fig.). Show that: (i) ΔAPD ≅ ΔCQB (ii) AP = CQ (iii) ΔAQB ≅ ΔCPD (iv) AQ = CP (v)…
4. ABCD is a rectangle in which diagonal AC bisects ∠A as well as ∠C. Show that: (i) ABCD is a square (ii) diagonal BD bisects ∠B as well as ∠D. Quadrilaterals Exercise 8.1 Previous Next Class 9 Quadrilaterals Exercise…
3. Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig.). Show that:(i) it bisects ∠C also, (ii) ABCD is a rhombus. Quadrilaterals Exercise 8.1 Previous Next Class 9 Quadrilaterals Exercise 8.1 1. If the diagonals of a parallelogram are…
2. Show that the diagonals of a square are equal and bisect each other at right angles. Quadrilaterals Exercise 8.1 Previous Next Class 9 Quadrilaterals Exercise 8.1 1. If the diagonals of a parallelogram are equal, then show that it…
1. If the diagonals of a parallelogram are equal, then show that it is a rectangle. Quadrilaterals Exercise 8.1 Previous Next Class 9 Quadrilaterals Exercise 8.1 1. If the diagonals of a parallelogram are equal, then show that it is…
8. In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see…
7. AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that ∠BAD = ∠ABE and ∠EPA = ∠DPB (see Fig.). Show that: (i) ΔDAP ≅ ΔEBP (ii)…