Solve the following equations:
12. (tan^{-1}{frac{1-x}{1+x}})(=frac{1}{2}tan^{-1}x,;(x>0))
Inverse Trigonometric Functions
Miscellaneous Exercise
Class 12
Inverse Trigonometric Functions
Miscellaneous Exercise
Find the value of the following:
1. (cos^{-1}(cosfrac{13pi}{6})).
2. (tan^{-1}(tanfrac{7pi}{6})).
3. (2sin^{-1}{frac{3}{5}})(=tan^{-1}{frac{24}{7}}).
4. (sin^{-1}{frac{8}{17}}+sin^{-1}{frac{3}{5}})(=tan^{-1}{frac{77}{36}}).
5. (cos^{-1}{frac{4}{5}}+cos^{-1}{frac{12}{13}})(=cos^{-1}{frac{33}{65}}).
6. (cos^{-1}{frac{12}{13}}+sin^{-1}{frac{3}{5}})(=sin^{-1}{frac{56}{65}}).
7. (tan^{-1}{frac{63}{16}}=sin^{-1}{frac{5}{13}})(+cos^{-1}{frac{3}{5}}).
8. (tan^{-1}{sqrt{x}}=frac{1}{2}cos^{-1}{frac{1-x}{1+x}}).
Solve the following equations:
11. (2tan^{-1}(cosx)=tan^{-1}(2cosecx)).
12. (tan^{-1}{frac{1-x}{1+x}})(=frac{1}{2}tan^{-1}x,;(x>0))
13. (sin(tan^{-1}x),|x|<1) is equal to:
14. (sin^{-1}(1-x)-2sin^{-1}x)(=frac{pi}{2}), then x is equal to:
