Statistics Class 10 Mcq Test (101301)

The class mark of a class interval is:

(a) Lower limit + Upper limit

(b) Upper limit – Lower limit

(c) \(\frac{1}{2}\)(Lower limit + Upper limit)

(d) \(\frac{1}{4}\)(Lower limit + Upper limit)

The mean and median of a data are 14 and 15 respectively. The value of mode is :

(a) 16

(b) 17

(c) 13

(d) 18

For a symmetrical distribution, which is correct?

(a) Mean > Mode > Median

(b) Mean < Mode < Median

(c) Mode = \(\frac{Mean+Median}{2}\)

(d) Mean = Median = Mode

If mode of the following data is 7, then value of k in 2, 4, 6, 7, 5, 6, 10, 6, 7, 2k + 1, 9, 7, 13 is:

(a) 3

(b) 7

(c) 4

(d) 2

If mode = 80 and mean = 110, then the median is:

(a) 110

(b) 120

(c) 100

(d) 90

If mode of a data is 45, mean is 27, then median is:

(a) 30

(b) 27

(c) 23

(d) None of these

The measures of central tendency which can’t be found graphically is:

(a) mean

(b) median

(c) mode

(d) none of these

The mean of the following data is: 45, 35, 20, 30, 15, 25, 40:

(a) 15

(b) 25

(c) 35

(d) 30